(Lecture 17 of Mathematical Methods II.)
A power series is a series of the form:
\begin{equation} \tag{1} a_0+a_1(z-z_0)+a_2(z-z_0)^2+\cdots+a_n(z-z_0)^n+\cdots \end{equation}
where $z$ is the (complex) variable, $a_i$ are constants called the coefficients of the series, and $z_0$ is also a constant, called the center of the series.
The convergence of Power Series is ruled by the following concept of radius of convergence:
The radius of convergence $R$ is that of the smallest circle that contains all the points where the series converges. No general statement can be made for points on the circle itself (cf. exercise 1).
The Cauchy--Hadamard formula allows to determine the Radius of convergence of a series from its coefficients:
\begin{equation} \mathrm{if\ } |a_{n+1}/a_n|\rightarrow L,\quad \mathrm{then\ }R=1/L. \end{equation}
For the following, with no loss of generality, we can assume the center is at $z_0=0$.
A power series has a unique representation, i.e., if $\sum a_iz^i=\sum b_iz^i$ for all $z$, then $a_i=b_i$ for all $i$.
radius of convergence $R_1$ and $R_2$ gives a power series with radius of convergence at least $\min(R_1,R_2)$.
\begin{equation} \tag{2} f(z)g(z)=\sum_{n=0}^\infty(a_0b_n+a_1b_{n-1}+\cdots+a_{n-1}b_1+a_nb_0)z^n \end{equation}
that converges in the smallest radius of convergence of the two series (unproven in class).
\begin{equation} \tag{3} \left(\sum_{n\ge0} a_nz^n\right)'=\sum_{n\ge1} na_n z^{n-1}=\sum_{n\ge0}(n+1)a_{n+1}z^n\,, \end{equation}
with the same radius of convergence.
\begin{equation} \tag{4} \int\left(\sum_{n\ge0} a_nz^n\right)\,dz=\sum_{n\ge0}\frac{a_n}{n+1}z^{n+1}\,, \end{equation}
with the same radius of convergence.
We will later see that Power Series are the analytic functions.